Three Doors and 1 Prize

Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick door No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to switch to door No. 2?" Wat will be your choice??

Solution to the 2 Mathematicians

The first clue was the product of their ages is 72.
So take all the possibilities.
72 ,1,1 = not possible coz mathematicians met after 27 years.
36, 2,1= not possible
18,2,2
9,4,2
4,6,3
6,6,2
12,3,2
12,6,1
24,3,1
3,3,8

Now the second clue is tat the sum of their ages is a number tat the other guy can clearly see.. But still the other guy cant guess the answer.
18,2,2 =22
9,4,2 =15
4,6,3 =13
6,6,2 = 14
12,3,2 =17
12,6,1 =19
24,3,1 = 28
3,3,8 = 14
So if the guy couldnt guess the answer tat means tat the total must hav been 14. thn u hav 2 possible ways u can factorise 72 wit the sum 14..
so the answer must be 6,6,2 or 8,3,3
The third clue says tat the youngest daughter just started walking.
So.. 8,3,3 s nt possible.. here u hav 2 younger daughters of the same age.

Therefore 6,6,2 is the answer :)

Solution to Cookie Seller

The solution goes lik this.. :)
We hav inifinte number of boxes of each type..
By taking all multiples of 6 we will get all the even multiples of 3 above 6.. and by taking all multiples of 9 we will be able to make all odd multiples of 3. Thus we can make all the multiples of 3 above the number 6..
So wat abt the the other numbers?? hmmm..
Now take the number 29.. it gives 2 as remainder when divided by 3.. if we add 400 to 29 ie 429 is a multiple of 3. So any number above 410 which gives a remainder of 2 when divided by 3 can be made by using a 400 box and the rest 6 and 9.
ie, 421= can be made as 400 + 21 ( 2 *6+1*9) and so on..
Now take the number 28. it gives a remainder 1 when divided by 3. If we add 800 to 28 ie 828 is divisble by 3..
So any number above 806 can be made by these 3 types of boxes..
So wat abt the maximum tat cannot be sold
805 - 400 is divisible by 3..
804 is divisible by 3
803 is nt divisble by 3, 803-400=403 is nt divisble by 3, a 803-800=3 cannot be made using our boxes..

So 803 is the max number of boxes tat cannot be sold..

Two mathematicians met after 27 years...

Two mathematicians met after 27 years in their college.

This was their conversation.
First: How are you doing?
Second: Fine I got married and have 3 daughters.
First: Fine. I also got married 2 years after the college. How old are your daughters?
Second: Well, Product of their ages is 72 and their sum is equal to that house number over there..(It was not mentioned).
First: Wait, I am still counting.
Second: Sorry, youngest of them just started walking.
First: Is it! Youngest of mine is also of the same age.

How old are the three daughters?

Cookie Seller

U r a cookie seller.. U hav 3 types of cookie boxes. They hav 6 or 9 or 400 cookies each. U hav infinite number of boxes of each type. Then wat is the maximum number of cookies u cannot sell ??

12 Coin Puzzle

This is our first puzzle..

U hav 12 identical coins out of which 1 has a slightly different weight (It may be heavier or lighter).U r given a balance and u r asked to find out the defective coin using the balance. Wat is the minimum number of trials required to find out the defective coin??

Puzzles Never Fascinated me.............

Puzzles Never Fascinated me.............until some weeks back.My friends used to solve all those puzzles and i just stood there watching it...It was some days back,when i tried solving one i realized how exciting it is when u find a solution to a puzzle...
We are trying to solve as many puzzles we can,and will be posting the solutions in here..The visitors to this blog can give their suggestions and can point out any discrepancy in the solutions.U can also post your puzzles too as comments and we will try to solve it too...Hope this would work out...